-16x^2-10x+450=0

Solution for -16x^2-10x+450=0 equation:

-16x^2-10x+450=0

a = -16; b = -10; c = +450;
Δ = b2-4ac
Δ = -102-4·(-16)·450
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28900}=170$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-170}{2*-16}=\frac{-160}{-32}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+170}{2*-16}=\frac{180}{-32}
=-5+5/8
$